Math, asked by addhyankumardubey1, 1 day ago

Note : Use elimination method for linear equations by forming 2 statements.

Question : A person invested some money at 12% sample interest and some other at 10% simple interest. He received yearly interest of ₹1300. If he had interchanged the amounts, he would have received ₹40 more as yearly interest. How much did he invest at different rates?

So, the equations are :
6x + 5y = 13000
5x + 6y = 13400

Coefficients equated to :
30x + 25y = 65000
30x + 36y = 80400

Subtracted to :
-11y = -15400
y = 1400
x = 1000

How do i calculate the investment then?
Please also correct my steps if they're wrong

ty <3​

Answers

Answered by shabhebhoi12
0

Answer:

1000$ and thank you very very nice

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