Note: -
You are
3
5
X is:
The general solution for x'
1 -1
1
-21
,21
a) x(t)=4
+ C2
1
1
C
0
b) x(t)=441
G
(19
)
d) x(0)=<(") (1)
+C₂
0
te
2
-21
c) x(t)=4
t
e
+C2
1
47
P
Answer
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0
Answer:
2xetan−1y=e2tan−1y+k
(1+y2)+(x−etan−1y)dxdy=0⇒(1+y2)dydx+x=etan−1y⇒dydx+1+y2x=1+y2etan−1y
Taking I.F=etan−1y
We get
x.I.F=∫y.I.Fdyxetan−1y=2e2tan−1y+k
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