notice that in first term there is 3x2 whole underroot
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√(3x²) + 10x -8√3=0
x√3 + 10x -8√3=0
x(√3 -10)=8√3
x=8√3/(√3 -10)
if you want to, you can rationalise the RHS terms, but not doing so is also okay.
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