Question

Now, by cauchy's inequality: | summation of i = 1 to n|: w[i])2 <= | summation of i = 1 to n|: (12)(summation of i = 1 to n)(w[i])2 | summation of i = 1 to n|: (w[i])^2 >= (((summation of i = 1 to n): w[i])2) / (summation of i = 1 to n)(12) >= (((n^2)((n-1)^2))/4)/n. >= (n*((n-1)^2))/4.

Answer 1

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