Now draw triangles of these specifications:
,•MN = 6 centimetres, ZM = 70°, ML = 5 centimetres.
• PQ = 7 centimetres, QR = 7 centimetres, ZQ = 50°
• XY = 6.5 centimetres, ZY = 110°, YZ = 7.5 centimetres.
• CD = 5 centimetres, DE = 5 centimetres, 2D = 60°.
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Answer:
1. Draw LN=7cm.
2. With L as centre and radius =6.4cm, draw an arc at M.
3. With N as centre and radius =5.5cm, draw an arc at M.
4. Join LM, MN.
5. Hence Δ LMN is the required triangle.
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