Question

Now imagine that a skateboarder is moving in a straight line at a constant speed of 3 m/s and comes to a stop in 2 s. What is the skateboarder’s acceleration?

Answer 1

Here,let u= 3m/s

v= 0m/s

t = 2 second

We know that, a=v-u/t

so putting the values,a= 0-3/2

a= -3/2

therefore , a= -1.5 m/s²

Explanation:

The skateboard is moving in a straight line so from the time where we are seeing the skateboard, it's initial velocity is 3m/s and after it stops after 2 second, it means that it's final velocity is 0 m/s and after putting these values to the formula of acceleration i.e. a= v-u/t.We get acceleration -1.5

Answer 2

The acceleration of the skateboarder is -1.5m/$s^{2}$

Given:

A skateboarder is moving in a straight line at a constant speed of 3 m/s and comes to a stop in 2 s.

To Find:

We have to find the skateboarder’s acceleration.

Solution:

The skateboard is moving in a straight line so, from the time where we are seeing the skateboard, it's initial velocity is 3m/s and after it stops after 2 seconds, it means that it's final velocity is 0 m/s and after putting these values to the formula of acceleration i.e. a= v-u/t.

Here,

u= 3m/s

v= 0m/s

t = 2 second

We know that,

a=v-u/t

So putting the values,a= 0-3/2

a= -3/2

Therefore , a= -1.5 m/s²

Hence, the acceleration of the skateboarder is -1.5m/$s^{2}$

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