Now, let's verify that I = 5 is indeed a solution to the equation 72 - 12 = 13 + 2x. On substituting
r = 5 in 70 - 12 = 13 + 2r, we'll get:
LHS = 7(5) - 12=
• RHS = 13+2x =
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Answer:
L.HS. = 7×5 - 12 = 35-12= 23
R.H.S.= 13 + 2×x = 13+ 2×5= 13+10 = 23
L.H.S = R.H.S ©
VERIFIED
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