now , my question is,,.. I'm not understanding how to write that1+1+3+1+3+5 from where that came
please help me out from this
if I got correct ANS with step by step with reasoning I will give 35 to thanks.+ follow u+ I will mark ur 20 answer with 5.0 rating.
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Answer:
spdf designates subshells. s subshells hold 1 orbital. p holds 3, d holds 5, f holds 7.
so, S=1,p=3,d=5,f=7
wherever there is s ,put the value 1 for that subshell ...for p,put 3....for d,put 5
In this way u can find the orbitals....
1s 2s 2p 3s 3p 3d
=>1(s)+1(s)+3(p)+1(s)+3(p)+5(d)
=1+1+3+1+3+5
=14(no. of orbital)
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Explanation:
please refer to the attached file
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