Now, show that AB + BC + AC < 2 (OA + OB + OC).
The length of two sides of a triangle are 4 cm and 6 cm. Between what two measure
should the length of the third side fall?
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Answer:
Making a triangle is possible only with sides given in option ‘b’. In other options, sum of two sides is either equal to or less than the third side.
Question 2: Take any point O in the interior of a triangle PQR. Is
triangles
OP + OQ > PQ?
OQ + OR > QR?
OR + OP > RP?
Answer: The answer is yes in each case, because sum of any two sides of a triangle is always greater than the third side.
Question 3: AM is a median of a triangle ABC. Is AB + BC + CA > 2AM? (Consider the sides of ΔABM and ΔAMC)
triangles
Answer: In ΔABM; AB + BM > AM
Similarly, in ΔAMC; AC + CM > AM
Adding above equations, we get;
AB + BM + CM + AC > 2AM
Or, AB + BC + CA > 2AM
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