Question

np2=30 then n=?? plz gentelman tell me about its answer.it's important for me.

Answer 1

Given:

nP2 = 30

To Find:

Value of n

Solution:

Expanding nP2 = 30

= n! / ( n - 2)! = 30

=n (n-1)(n-2)!/(n-2)! = 30

n(n-1) = 30

n² - n - 30 = 0

n² - 6n +5n - 30 = 0

n (n-6) + 5(n-6) = 0

(n+5)(n-6) = 0

n= -5 0r n = 6

Since, the value of n can not be negative.

Thus, n = 6

Answer: The value of n is 6.

Answer 2

Answer:

The result will be $n=6$ and $-5$

Step-by-step explanation:

In accordance with the information provided in the question,

Given the data in question $np^{2} =30$

We have find the value of n in the above question

As we get,

$np2=30$

[tex]n(n-1)=30\\ n^{2} -n=30\\ n^{2} -n-30\\=0 n^{2} -6n+5n-30=0\\ n(n-6)+5(n-6)=0\\ (n-6)(n+5)=0\\ n-6=0\\ n=6\\ n-5=0\\ n=-5[/tex]

Hence the result will be n$=6$ and $-5$