Question

nP3= 9240
, find tha value of n​

Answer 1

Answer:

n=22

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Step-by-step explanation:

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$nPr=n!/(n-r)!$

here, n=?

r=3

nP4=9240

9240=n!/(n-3)!

9240=(n(n-1)(n-2)(n-3)!)/(n-3)!  (Expanding n!)

9240=n(n-1)(n-2)

22*21*20=9240

hence answer is 22.

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