nple 5: Find the roots of the quadratic equation 3x² - 2/6x +2=0.
Answers
Answered by
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Step-by-step explanation:
3
2
−
1
⋅
2
6
⋅
+
2
=
0
3x^{2}-1 \cdot \frac{2}{6} \cdot x+2=0
3x2−1⋅62⋅x+2=0
Quadratic formula
1
Divide the numbers
3
2
−
1
⋅
2
6
⋅
+
2
=
0
3x^{2}-1 \cdot {\color{#c92786}{\frac{2}{6}}} \cdot x+2=0
3x2−1⋅62⋅x+2=0
3
2
−
1
⋅
1
3
+
2
=
0
3x^{2}-1 \cdot {\color{#c92786}{\frac{1}{3}}}x+2=0
3x2−1⋅31x+2=0
2
Multiply the numbers
3
2
−
1
⋅
1
3
+
2
=
0
3x^{2}{\color{#c92786}{-1}} \cdot {\color{#c92786}{\frac{1}{3}}}x+2=0
3x2−1⋅31x+2=0
3
2
−
1
3
+
2
=
0
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