NPR=840,NCR=35 find n and r
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Step-by-step explanation:
1 ) nPr. = n!/( n - r )!
2 ) nCr = n!/ [ ( n - r )! r ! ]
3 ) r ! = ( nPr )/ nCr
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It is given that ,
nPr = 840 ---( 1 )
nCr = 35 ---( 2 )
r ! = ( nPr )/ ( nCr )
= 840/35
= 24
r ! = 4 × 3 × 2 × 1
r ! = 4!
Therefore,
r = 4
Substitute r value in equation ( 1 ),
We get
n!/ ( n - 4 ) ! = 840
n( n - 1 )( n - 2 )( n - 3 ) = 840
n( n - 1 )( n - 2 )( n - 3 ) = 7× 6 × 5 × 4
Therefore ,
n = 7
I hope this helps you.
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