Question

ns.
12. In a circuit, three resistances of 1022, 612 and 4
are connected in series combination. The potential
difference of the entire combination is 10 volt.
Find current and potential difference in each
resistance.
(2011)
622
1092
www
422
M
А
B
+7
10V
Fig. 12.42
[Ans. 5.0 V, 0.3V, 2.0V​

Answer 1

Answer:

In this case, 2 resistances of 6 ohms and 4 ohms are connected in series. So the total resistance is given as 6+4 = 10 ohms.

The potential difference across the circuit is given as 20 V. The current in the circuit can be determined from the relation I=

R

V

=

10

20

A=2 A.

Hence, the current in the circuit is 2 ampere.

As the current is same across a serially connected circuit, the voltage across the 6 ohms resistor can be determined using the relation: V=IR.

That is, V=2A×6Ω=12 V.

Hence, the potential difference across the 6 ohms resistor is 12 V.

Answer 2

Answer:

no no no no no no no no no no