Nstead of multiplying a number by 7, the number is divided by 7. what is the percentage of error obtained
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let n be the number to be multiplied by 7
then,
a=7n
but it is divided by 7 instead of multiplying with 7.
then
| ∆a |=| n/7 - 7n |
| ∆a |=| n(1 - 49)/7 |
| ∆a |=| n(-48)/7 |
∆a = 48n/7
So,
percentage error,
δa = [(48n/7)×(1/7n)]×100
δa = 100×48/49
δa = 97.95 %
then,
a=7n
but it is divided by 7 instead of multiplying with 7.
then
| ∆a |=| n/7 - 7n |
| ∆a |=| n(1 - 49)/7 |
| ∆a |=| n(-48)/7 |
∆a = 48n/7
So,
percentage error,
δa = [(48n/7)×(1/7n)]×100
δa = 100×48/49
δa = 97.95 %
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