Question

NT
then find the value of x.
(5) If sin '(1-x) - 2 sin-' x =​

Answer 1

Answer:

Step-by-step explanation:

Given that sin  

−1

(1−x)−2sin  

−1

x=  

2

π

​  

 

let x=siny

∴sin  

−1

(1−siny)−2y=  

2

π

​  

 

⇒sin  

−1

(1−siny)=  

2

π

​  

+2y

⇒1−siny=sin(  

2

π

​  

+2y)

⇒1−siny=cos2y

⇒1−siny=1−2sin  

2

y as cos2y=1−2sin  

2

y

⇒2sin  

2

y−siny=0

⇒2x  

2

−x=0

⇒x(2x−1)=0

⇒x=0,2x−1=0

⇒x=0,2x=1

⇒x=0,x=  

2

1

​  

 

But x=  

2

1

​  

 does not satisfy the given equation  

∴x=0 is the solution of the given equation.