Math, asked by t19584das, 1 day ago

nth derivative of x^2+x+1​

Answers

Answered by saravananmaya1
1

Answer:

f(x)= 1−x 21= (1−x)(1+x)1

= 21 [1−x1+ 1+x1]dxndnf(x)

=21dxndn( 1+x1 )+21dxndn( 1+x1 )

=21(1−x)n+1(−1) n.n!(−1) n+21(1+x)n+1(−1)n.n!(1)n

When n is even

= 21(1−x)n+1n!+21(1+x)n+1n!

∴ at x=0dxndnf(x)

= 21.1nn+21. 1n!

= 21.2n!dxndnf(o)

=n! , when n is even .

Step-by-step explanation:

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