nth derivative of x^2+x+1
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Answer:
f(x)= 1−x 21= (1−x)(1+x)1
= 21 [1−x1+ 1+x1]dxndnf(x)
=21dxndn( 1+x1 )+21dxndn( 1+x1 )
=21(1−x)n+1(−1) n.n!(−1) n+21(1+x)n+1(−1)n.n!(1)n
When n is even
= 21(1−x)n+1n!+21(1+x)n+1n!
∴ at x=0dxndnf(x)
= 21.1nn+21. 1n!
= 21.2n!dxndnf(o)
=n! , when n is even .
Step-by-step explanation:
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