Question

nth derivative of x/2x^2+3x+1​

Answer 1

1. step

let, function f(x)= x/2x^2+3x+1

= 1/2x + 3x + 1

now, differentiating w.r.to x we get

df(x)/dx = 1/2x^2 + 3 + 0

again, differentiating w.r.to x we get

f(x)"= -x^3

again , differentiating w.r.to x we get

f(x)"' = -3x^2

again........

f(x)"" = -6x

again......

f(x)""'= -6 ans