Math, asked by motabaherali, 1 year ago

nth derivative of y=x^2n

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Answered by Anonymous
0
Generally, for y=x^{m} n-the derivative is \frac{d^{n}y}{dx^{n}}=\frac{m!}{(m-n)!}x^{m-n} for n≤m otherwise 0.
Here it's \frac{(2n)!}{n!}x^{n} .
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