Question

nth term of an AP is given by 5n-3 find AP

Answer 1



Kiran Notay answered this

an=5n-3 
let n=1 
a=5(1)-3 
=2 
let n=2 
a2=5(2)-3 
=7 
therefore ap= 2,7... 
Sn= n/2{2a+(n-1)d} 
=20/2{2(2)+(20-1)5} 
=10{4+(19)5} 
=10(4+95) 
=990

Answer 2

nth term of AP = 5n-3
1st term of AP = 5 (1) - 3
= 5 -3
= 2

Second term of AP = 5 (2) -3
= 10 -3
= 7

Third term = 5 (3) - 3
15 - 3
= 12

So AP is 2,7,12..... with common difference = 5.

Hope it helps.