Question

nth term of ap is n^2-1 then n+1 th term of ap is ?

Answer 1

Step-by-step explanation:

Given:

$t_n = {n}^{2} - 1 \\ substituting \: (n + 1) \: in \: place \: of \: \\ n \: we \: find: \\ t_{(n + 1)} = {(n + 1)}^{2} - 1 \\ \implies \: t_{(n + 1)} = {n}^{2} + 2n + 1 - 1 \\ \implies \: \huge \fbox{t_{(n + 1)} = {n}^{2} + 2n }$