Question

nth term of series (1^3/1)+(1^3+2^3/1+2)+(1^3+2^3+3^3/1+2+3).............is

Answer 1

$\frac{ {1}^{3} + {2}^{3} + {3}^{3} + ... + {n}^{3} }{1 + 2 + 3 + ... + n} = \frac{n^{2} (n+1) ^{2} \div 4 }{n(n + 1) \div 2} = n(n+1) \div 2$