Question

(ntse exam question) Two bodies with kinetic energies in the ratio 4 : 1 are moving with equal linear momentum. The ratio of their masses is : (1) 1 : 2 (2) 1 : 1 (3) 4: 1 (4) 1 : 4

Answer 1

Linear Momentum, p = mv
Kinetic energy = 0.5mv² = p²/2m

$\frac{KE_1}{KE_2} = \frac{1}{4} \\ \\ \Rightarrow \frac{p^2/2m_1}{p^2/2m_2} = \frac{1}{4} \\ \\ \Rightarrow \frac{m_2}{m_1} = \frac{1}{4} \\ \\ \Rightarrow \frac{m_1}{m_2} = \frac{4}{1}=\boxed{4:1}$

Answer 2

Answer:

Explanation:

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