Question

nu
11
5 Find the product.
(5 - 2d - $)(3 - 2d)
rah + 4lat 2)
(9262 ​

Answer 1

Here is given, (5-2d-d^2)(3-2d)

= (15-6d-3d^2-10d+4d^2+2d^3)

= (2d^3 +4d^2-3d^2-6d-10d+15)

= (2d^3+d^2 - 16d+15)

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