Question

Nu Me- ÇH – CH2 -X gives the CH – C—CH, CH, CH; on treatment with a nucleophile. In which condition, the yield of product will be maximum
​

Answer 1

Answer:

CH

2

−I+C

2

H

5

I

The reaction is written as:

CH

3

−

CH

∣

CH

3

−CH

2

−O−C

2

H

5

+HI

△

HC(CH

3

)

2

−CH

2

−I+C

2

H

5

I

When a mixed ether is heated with HI, it gives two different alkyl iodides.