Nuclear radius R has a dependence on the mass number (A) as R=1.3×10^(-16) A^(1/3) m.For a nucleus of mass number A=125, obtain the order of magnitude of R expressed in metre?
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Answer: -15
Explanation:order of magnitude : it is used scientific notation. if any number X in such a way that X = m × 10^n , where m belongs to then, 10ⁿ is known as order of magnitude.
given, nucleus radius R has a dependence on the mass number (A) as R = 1.3 × 10^-16 × A⅓ m.
for a nucleus of mass number , A = 125
R = 1.3 × 10^-6 × (125)⅓
= 1.3 × 10^-6 × (5³)⅓
= 1.3 × 10^-6 × 5 = 6.5 × 10^-16 m
but we know, 6.5 > √10
so, resolve 6.5 in such a way that it lies between √10/10 to √10.
we see, √10/10 < 0.65 < √10
hence, R = 6.5 × 10^-16 = 0.65 × 10^-15 m
here order of magnitude is 10^-15 or simply it can be written as -15.
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