Question

Nuclear radius R has a dependence on the mass number (A) as R = 1.3×10^-16) A^1/3m .For a nucleus of mass number A = 125 , obtain the order of magnitude of R expressed in meter.

Answer 1

Answer:

hey Mate here is your answer.....

It is given that,

It is given that,The nuclear radius R depends on the mass number as :

A is the mass number of the atom

Here, A = 125

Use A in above formula as :

or

It is clear from the above value that the order of the nuclear radius is (-15). Hence, this is the required solution

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order of magnitude : it is used scientific notation. if any number X in such a way that X = m × 10^n , where m belongs to \left[\frac{\sqrt{10}}{10},\sqrt{10}\right] then, 10ⁿ is known as order of magnitude.

given, nucleus radius R has a dependence on the mass number (A) as R = 1.3 × 10^-16 × A⅓ m.

for a nucleus of mass number , A = 125

R = 1.3 × 10^-6 × (125)⅓

= 1.3 × 10^-6 × (5³)⅓

= 1.3 × 10^-6 × 5 = 6.5 × 10^-16 m

but we know, 6.5 > √10

so, resolve 6.5 in such a way that it lies between √10/10 to √10.

we see, √10/10 < 0.65 < √10

hence, R = 6.5 × 10^-16 = 0.65 × 10^-15 m

here order of magnitude is 10^-15 or simply it can be written as -15.

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Answer 2

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order of magnitude : it is used scientific notation. if any number X in such a way that X = m × 10^n , where m belongs to then, 10ⁿ is known as order of magnitude.

given, nucleus radius R has a dependence on the mass number (A) as R = 1.3 × 10^-16 × A⅓ m.

for a nucleus of mass number , A = 125

R = 1.3 × 10^-6 × (125)⅓

= 1.3 × 10^-6 × (5³)⅓

= 1.3 × 10^-6 × 5 = 6.5 × 10^-16 m

but we know, 6.5 > √10

so, resolve 6.5 in such a way that it lies between √10/10 to √10.

we see, √10/10 < 0.65 < √10

hence, R = 6.5 × 10^-16 = 0.65 × 10^-15 m

here order of magnitude is 10^-15 or simply it can be written as -15.

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