Physics, asked by parichaydebbarm371, 9 months ago

Nuclei of radioactive element A are produced at rate 't^(2') (where t is time) at any time t. The element A has decay constant lambda. Let N be the number of nuclei of element A at any time t. At time t=t_(0), dN//dt is minimum. The number of nuclei of element A at time t=t_(0) is

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Answered by saswatkumarsingh123
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