Question

number?
1. Sum of the digits of a two digit number is 11. When we interchange the digits, it is
found that the resulting new number is greater than the original number by 63. Find
the two digit number​

Answer 1

Step-by-step explanation:

Let the unit digit be y and tens digit be x

Number formed = 10x + y

Reverse number = 10y + x

x + y = 9 (Given)…………………………eq1

10y + x = 10x + y + 27…………………….eq2

9y - 9x = 27

y - x = 3……………………………………..eq3

Solving eq1 and eq3 ,we get

x = 3 and y = 6

Original Number = 36 Reversed Number = 63

You can crosscheck the answer by putting up the values obtained either in eq1 or eq2 or eq 3

Thank You !

Answer 2

Answer:

Let the tens digit be x and ones digit be y

Number  = 10x - y

Interchanged number = 10y- x

x+y  = 11(X 11)

11x + 11y =121

11x = 121 - 11y

10y - x - 10x + y = 63

11y - 11x = 63

11y -121 +11y  = 63

22y = 184

11y = 92

y = 8

x = 2

Step-by-step explanation: