Question

number
13. ABC - DEF such that ar(ABC) = 54cm' and arDEF) = 159 cm
PBC = 4 cm. then
length of side EF is ......... cm​

Answer 1

Answer:

$\huge\underline\mathtt\red{Answer}$

=96cm²

$\large\underline\mathtt\green{Explination}$

For similar triangles

For similar triangles ( EF/BC)²=ArΔDEF/ArΔABC

(3/4)²=54/ ArΔDEF

ArΔDEFAr(ΔDEF)=54×16/9

=96cm².

.

I hope this helps you........

Answer 2

Answer:

For similar triangles

For similar triangles ( EF/BC)²=ArΔDEF/ArΔABC

(3/4)²=54/ ArΔDEF

ArΔDEFAr(ΔDEF)=54×16/9

=96cm².

.

I hope this helps you........