Question

Number
Divisible by 2
Divisible by 3
Divisible by 5
Divisible by
10
Divisible by2 : 3207
divisible by 3: 2138
divisible by 5: 1282.8
divisible by 10: 641.4
​

Answer 1

Answer:

A no. is divisible by 2 if the last digits are 2,4,6,8,0.

for divisibility for 3 sum of digits of no should be divisible by 3 and in case of 5 last digit should be 0,5 and for ten last digits should be, 0

Answer 2

Step-by-step explanation:

Divide By 2 :

1. If you divide 3207 by 2 and the quotient is an integer, then 3207 is divisible by 2. 3207 divided by 2 is 1603.5. 1603.5 is not an integer, thus 3207 is not divisible by 2
2. To find out if 2138 is divisible by 3, we will add up the digits that make 2138 as follows: 2 + 1 + 3 + 8 = 14
4. We know that if the sum of the numbers that make up 2138 is divisible by 3, then 2138 is divisible by 3.
6. Since the sum of the digits in 2138 is not divisible by 3, 2138 is also NOT divisible by 3. Thus, the answer to the question "Is 2138 divisible by 3?" is as follows:
7. Six thousand, four hundred and fourteen divided by five is 1282.8. Math: 6414÷5=1282.8