number of atom present in 0.5 g atom of nitrogen is same as the atom in
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1. 24 gram mg 2. 8g of oxygen 3. 32g sulphur 4. 12g carbon
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no. of atoms present in 0.5 gm of N = 0.5 gm ✖ [ 1mole / 14 gm ]✖[ 6.022 *10^23 / 1 mole ]
= 0.5* 6.022 *10^23 / 14 atoms
= 0.215 *10^23 atoms of N
= 0.5* 6.022 *10^23 / 14 atoms
= 0.215 *10^23 atoms of N
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