Question

number of atom
present in 11.4 litre of methane at NTP​

Answer 1

1 mole =22.4 litre at NTP

thus 11.4 litre contain=11.4/22.4 = 0.5mole

1 mole contain =6.23×10^23 molecules

thus 0.5 mole contain=0.5×6.23×10^23

= 3.0115×10^23 molecules

1molecule contain 5 atoms

therfore 3.0115×10^23 molecules

contain= 3.0115× 10^23 ×5

=15.0575×10^23 atoms