NUMBER OF ATOMS IN 104g OF He
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Answer:-
1.565×10²⁶ molecules
Explanation:-
Given:-
→ Mass of Helium (He) = 104g
To find:-
→ Number of atoms
Solution:-
• Atomic mass of Helium (He) = 4u
Since, atomic mass of He is 4u, thus it's molar mass will be 4g/mol.
Firstly, let's calculate the number of moles in 104g of He.
No of moles = Given Mass/Molar mass
= 104/4
= 26 moles
• Avogadro Number = 6.022×10²³
No of atoms
= No of moles × Avogadro Number
= 26×6.022×10²³
= 156.572×10²³
= 1.565×10²⁶ atoms
Thus, 1.565×10²⁶ atoms are there.
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