Question

Number of atoms in 34.20 grams of cane sugar​

Answer 1

C12H22O11

given mass/molecular mass = no of moles

34.2/342=0.1 mole

no of atoms = avogardo constant*no of moles*atomicity

=6.022*10²³ *0.1*45

=270.99*10²²

=271*1022

=2.71*10^24atoms

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Answer 2

here your answer

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