Number of atoms in 85u of NH3
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Answered by
0
Your answer is ---
molecular mass of NH3 = 14+1×3 = 17u
So, moles of NH3 = 85/17 mol = 5mol
Number of molecules = 5 × NA (Avogadro number )
= 5 × NA = 5×6.023×10^23
= 30.115 × 10^23 molecules
Now, NH3 contain
3hydrogen atom and 1 nitrogen atom. total 4 atom .
so,number of atom =
4 × 30.115 × 10^23
= 120.46 × 10^23 atoms
【 Hope it helps you 】
molecular mass of NH3 = 14+1×3 = 17u
So, moles of NH3 = 85/17 mol = 5mol
Number of molecules = 5 × NA (Avogadro number )
= 5 × NA = 5×6.023×10^23
= 30.115 × 10^23 molecules
Now, NH3 contain
3hydrogen atom and 1 nitrogen atom. total 4 atom .
so,number of atom =
4 × 30.115 × 10^23
= 120.46 × 10^23 atoms
【 Hope it helps you 】
Answered by
0
molecular weight of NH3=17 amu
given molar weight=85amu
so no of moles=85/1=5moles
no of H atoms in one mole=3
so no of H aoms in moles=3*5=15 atoms
hope this will help you
given molar weight=85amu
so no of moles=85/1=5moles
no of H atoms in one mole=3
so no of H aoms in moles=3*5=15 atoms
hope this will help you
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