Question

Number of atoms of oxygen present in 3.6 L of SO2 gas at STP is:​

Answer 1

Explanation:

At STP 22.4 L of volume is occupied by 1 mole of gas.

So 5.6 L is occupied by 5.6/22.4 = 0.25 moles.

1 mole= 6.022 X 10^23 molecules

=> 0.25 moles= 1.5055 X 10^23 molecules.

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Answer 2

Answer:

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