Question

Number of atoms of oxygen present in 48 u of ozone molecule is : (1)3 x 6.022 x 10^23 (2) 6 x 6.022 x 10^23 (3) 3 (4) 48

Answer 1

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Ozone is O3 molar mass = 48 gm/mol

48 gm /48 g/mol = 1mol

avocadro no = 6.023 * 10^23 atom

1mol * 6.023 * 10 ^ 23 * 3 atom = 18.069 * 10^23 = 1.8 069 * 10^24 atom