number of atoms present in 1.6 g CH4
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No. Of atoms of CH4 = NO. of mole* 6.023 *10^23
: 1.6/16 * 6.023*10^23
: 0.1*6.023*10^23
:6.023*10^22 atoms.
: 1.6/16 * 6.023*10^23
: 0.1*6.023*10^23
:6.023*10^22 atoms.
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