Question

Number of atoms present in 18gram of glucose

Answer 1

Answer:--

Glucose is C6H12O6, with a molar mass of approximately 180 grams, so 18 grams is 0.1 moles. 0.1 X Avagadro's number = 6.02 x 10 exp24 x 6(number of carbons in each 0.1 mole) = 3.60 x 10 exp23.