Question

Number of atoms present in 3.7g mole of nitrogen is how much

Answer 1

Answer:

Explanation:

we know that

no. of moles = given mass /molar mass

so,

n=3.7/14= 0.26moles

we also know that

number of moles = given no. of atoms/molecules / avagadro no.

0.26=x/6.022*10*23

x=6.022*0.26*10^23

x=1.565*10^23

therefore no. of atoms =1.565*10^23

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