Number of atoms present in 3 moles of iron is
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Answer:
The number of iron (Fe) atoms present in a pure sample of solid iron with a mass of 10 grams is equal to
(55.9)
(10.0)(6.02×10
23
)
Hence, the option (C) is the correct answer.
Note :
(55.9)
(10.0)
represents the ratio of mass of iron to molar mass. It represents number of moles of iron.
When number of moles of iron is multiplied with avogadro's number (6.02×10
23
), we get number of iron atoms. (The atomic mass of iron is 55.9)
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