Question

Number of atoms present in 32 u of Helium if the atomic mass of Helium is 4 u
5
6
7
8
Q​

Answer 1

1 Atom——> 4U
? Atom——>32U

By cross multiplication:
X Atom=32x1/4
X=8 Atoms.

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Answer 2

Number of atoms= weight of element/ gram atomic weight

here in the question weight of the element=32

gram atomic weight= 4

then no. of atoms= 32/4=8

so,no. of atoms =8