Question

number of atoms present in 34 gram of chlorine​

Answer 1

Answer:

.......,...........

Answer 2

Answer:

1 mole

Explanation:

We know atomic mass of Cl as 35.5

so

no of atoms= mass in gram /GAM

34g / 35.5 g

34 g/ (35.5 g/6.022 x 10^23)

approximately = 6.022 x 10^23 atoms

= 1 mole atoms( Avogadro's no. )