Question

number of atoms present in 49 g of H2SO4 IS​

Answer 1

Answer:

The molecular mass of H2SO4 =(2*1)+32+ (4*16)

=98g

So,98 g of H2SO4 contains 6.023*10^23 molecules…

Therefore,49g of H2SO4 contains 3.011*10^23 molecules…

So no.of atom present =(2+1+4)=7

So…no.of atoms present in 49g of H2SO4

=(7*3.011*10^23)=2.107*10^24…

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Answer 2

see this attachment

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