number of atoms present in 4g of h2o2
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Answer:
~2.834 × 10^23 atoms
Explanation:
Molar mass of H2O2 is = 34 g
Given mass of H2O2 is = 4 g
Therefore, no. of moles present in 4 g H2O2 = 4/34
By mole concept
We know that 1 mole of H2O2 contains = 6.023 × 10^23 molecules of H2O2
therefore, 4/34 moles of H2O2 contain = 4/34 × 6.023 × 10^23 molecules of H2O2
Now, 1 molecule of H2O2 contains = 4 atoms ( 2 oxygen and 2 hydrogen )
Therefore, 4/34 × 6.023 × 10^23 molecules contain = 4/34 × 6.023 × 10^23 ×4 atoms
which comes out to be
~2.834 × 10^23 atoms
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