Chemistry, asked by moriumnesa, 1 year ago

Number of atoms present in 52 g of helium is:
(NA is Avogadro's constant Gram atomic mass of He is 4 g)
(1) 26 X NA (ii) NA (iii) 13 X NA (iv) 52 X NA​

Answers

Answered by spotdukheviiia89
5

Hey mate ,

Here is the ans u r searching for....❤️❤️

Attachments:

spotdukheviiia89: please mark as brainliest.....
moriumnesa: ok
Answered by praru26
0

(iii) 13 X NA is the answer

Similar questions