Question

number of bits increase from fewest (on the left) to most (on

Answer 1

Java defines four integer types: byte, short, int, and long. All of these are signed, positive and negative values. Java does not support unsigned, positive-only integers. Many other computer languages, including C/C++, support both signed and unsigned integers. However, Java's designers felt that unsigned integers were unnecessary.

Specifically, they felt that the concept of unsigned was used mostly to specify the behavior of the high-order bit, which defined the sign of an int when expressed as a number. Java manages the meaning of the high-order bit differently, by adding a special "unsigned right shift" operator. Thus, the need for an unsigned integer type was eliminated.

The width of an integer type should not be thought of as the amount of storage it consumes, but rather as the behavior it defines for variables and expressions of that type. The Java run-time environment is free to use whatever size it wants, as long as the types behave as you declared them. In fact, at least one implementation stores bytes and shorts as 32-bit (rather than 8- and 16-bit) values to improve performance, because that is the word size of most computers currently in use.