Number of bonding pairs and lone pairs around the central atom in the Br3-ion are respectively
1)2,2 2)3,2 3)2,3 4)4,3
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Answer:
H=
2
1
[V+M−C+A]
where,
H= Number of orbitals involved in hybridization.
V=Valence electrons of the central atom.
M- Number of monovalent atoms linked to a central atom.
C= Charge of a cation.
A= Charge of an anion.
Consider the hybridization and shape of the options:-
A) I
3
−
H=
2
1
[7+2+1]=5.
⇒sp
3
d hybridized state with 3 lone pairs.
Linear in shape.
It has 2 bond pairs.
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