Number of Ca^+2 and Cl^- ion in 111g of anhydrous CaCl2 are
(A) Nα , 2Nα
(B) 2Nα , Nα
(C) Nα , Nα
(D) None
Explaination required..
No Spam..
NOTE -
here,
Nα = Avogadro's Number
Answers
Answered by
22
Answer:
(A) Nα , 2Nα
Explanation:
Molecular mass of CaCl2 is
- 40 + 35.5 × 2
- 40 + 71
- 111 gram
No. of moles × Gram molecular mass = Mass
- No. of moles = 111/111
- No. of moles = 1
Now,
- No. of Ca in CaCl2 is
- 1 × 6.022 × 10²³
- 6.022 × 10²³
Nα
And
- No. of Cl2 in CaCl2 is
- 1 × 2 × 6.022 × 10²³
2Nα
Avogadro's Number , Nα = 6.022 × 10²³
Answered by
4
A.) Na , 2Na
hope u like it
Similar questions
Business Studies,
7 months ago
Math,
7 months ago
Accountancy,
7 months ago
Chemistry,
1 year ago
Chemistry,
1 year ago